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ext中ComboBox+Ajax+分頁聯動代碼和注釋

今天花了1下午時間研究出了ComboBox+Ajax+分頁聯動效果.ext學習初步見效下面代碼直接就能運行,用list模擬了數據庫中取數據以下是目錄結構以下是代碼test1.jsp<%@pagelanguage="java"import="java.util.*"pageEncoding="UTF-8"%></span> <p class="auth-span"> <span id="br5n5555bvll" class="muted"><i class="fa fa-user"></i><span id="br5n5555bvll" class="zj-icon-text">系統</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-clock-o"></i><span id="br5n5555bvll" class="zj-icon-text">2019-08-29 22:28:19</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-eye"></i><span id="br5n5555bvll" class="zj-icon-text">2050</span></span>  </p> </article><article class="excerpt"> <header> <a title="編程技術" class="label label-important zj-del-target" href="/category/30">編程技術<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/14904" title="每位開發人員都應銘記的10句編程諺語" target="_blank" onclick="return recordId('',)">每位開發人員都應銘記的10句編程諺語 </a> </h2> </header> <div id="br5n5555bvll" class="focus"> <a class="zj-del-target" href="/article/14904" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/14.jpg" alt="" title=""></a> </div> <span id="br5n5555bvll" class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/14904';}else{window.open('/article/14904');}" style="cursor: pointer;">ASP.NET開發者KevinPang曾發表一篇博文《10ProgrammingProverbsEveryDeveloperShouldKnow》，文中列舉了版主認為開發者應該銘記的10條編程諺語。《職場博客——伯樂在線》對本文進行了翻譯，現把譯文轉載于此。全文如下：所謂諺語，就是用言簡意賅、通俗易懂的方式傳達人生箴言和普遍真理的話，它們能很好地幫助你處理生活和工作上的事情。也正因如此，我才整理了10句編程諺語，每位開發人員都應該銘記他們，武裝自己。1.無</span> <p class="auth-span"> <span id="br5n5555bvll" class="muted"><i class="fa fa-user"></i><span id="br5n5555bvll" class="zj-icon-text">系統</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-clock-o"></i><span id="br5n5555bvll" class="zj-icon-text">2019-08-29 22:21:39</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-eye"></i><span id="br5n5555bvll" class="zj-icon-text">2050</span></span>  </p> </article><article class="excerpt"> <header> <a title="各行各業" class="label label-important zj-del-target" href="/category/38">各行各業<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/10919" title="2007LA 3902 網絡(樹+貪心)" target="_blank" onclick="return recordId('',)">2007LA 3902 網絡(樹+貪心) </a> </h2> </header> <div id="br5n5555bvll" class="focus"> <a class="zj-del-target" href="/article/10919" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/13.jpg" alt="" title=""></a> </div> <span id="br5n5555bvll" class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/10919';}else{window.open('/article/10919');}" style="cursor: pointer;">https://icpcarchive.ecs.baylor.edu/index.php?option=com_onlinejudge&Itemid=8&category=283&page=show_problem&problem=1903題意：在一個樹狀的網絡中，提供VOD服務，葉子節點是客戶端，其他是服務器，要減少網絡延遲，所以要在其他的服務器也安裝同樣的服務，使得每臺客戶端到最近服務器的距離不超過k，求最少安裝服務的服務器。思路：一個關鍵點是選擇u節</span> <p class="auth-span"> <span id="br5n5555bvll" class="muted"><i class="fa fa-user"></i><span id="br5n5555bvll" class="zj-icon-text">系統</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-clock-o"></i><span id="br5n5555bvll" class="zj-icon-text">2019-08-12 09:27:42</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-eye"></i><span id="br5n5555bvll" class="zj-icon-text">2050</span></span>  </p> </article><article class="excerpt"> <header> <a title="各行各業" class="label label-important zj-del-target" href="/category/38">各行各業<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/10435" title="CloudStack添加新的API注意事項" target="_blank" onclick="return recordId('',)">CloudStack添加新的API注意事項 </a> </h2> </header> <div id="br5n5555bvll" class="focus"> <a class="zj-del-target" href="/article/10435" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/9.jpg" alt="" title=""></a> </div> <span id="br5n5555bvll" class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/10435';}else{window.open('/article/10435');}" style="cursor: pointer;">1、***Cmd上面的@APICommand里的responseObject關聯對于的Response；2、在tomcatconf/command.properties.in添加新API的權限；3、為得到Cmd，都需要實現PluggableService接口的getCommands()方法，核心Cmd都需在ManagementServerImpl類的getComands()方法里將新添加的***Cmd類添加到cmList中。CloudStack添加新的AP</span> <p class="auth-span"> <span id="br5n5555bvll" class="muted"><i class="fa fa-user"></i><span id="br5n5555bvll" class="zj-icon-text">系統</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-clock-o"></i><span id="br5n5555bvll" class="zj-icon-text">2019-08-12 09:27:26</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-eye"></i><span id="br5n5555bvll" class="zj-icon-text">2050</span></span>  </p> </article><article class="excerpt"> <header> <a title="各行各業" class="label label-important zj-del-target" href="/category/38">各行各業<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/9811" title="ccf認證模擬題之三---最大的矩形" target="_blank" onclick="return recordId('',)">ccf認證模擬題之三---最大的矩形 </a> </h2> </header> <div id="br5n5555bvll" class="focus"> <a class="zj-del-target" href="/article/9811" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/16.jpg" alt="" title=""></a> </div> <span id="br5n5555bvll" class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/9811';}else{window.open('/article/9811');}" style="cursor: pointer;">問題描述在橫軸上放了n個相鄰的矩形，每個矩形的寬度是1，而第i（1≤i≤n）個矩形的高度是hi。這n個矩形構成了一個直方圖。例如，下圖中六個矩形的高度就分別是3,1,6,5,2,3。請找出能放在給定直方圖里面積最大的矩形，它的邊要與坐標軸平行。對于上面給出的例子，最大矩形如下圖所示的陰影部分，面積是10。輸入格式第一行包含一個整數n，即矩形的數量(1≤n≤1000)。第二行包含n個整數h1,h2,…,hn，相鄰的數之間由空格分隔。(1≤hi≤10000)。</span> <p class="auth-span"> <span id="br5n5555bvll" class="muted"><i class="fa fa-user"></i><span id="br5n5555bvll" class="zj-icon-text">系統</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-clock-o"></i><span id="br5n5555bvll" class="zj-icon-text">2019-08-12 09:27:06</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-eye"></i><span id="br5n5555bvll" class="zj-icon-text">2050</span></span>  </p> </article><article class="excerpt"> <header> <a title="各行各業" class="label label-important zj-del-target" href="/category/38">各行各業<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/9656" title="sublime 快捷鍵" target="_blank" onclick="return recordId('',)">sublime 快捷鍵 </a> </h2> </header> <div id="br5n5555bvll" class="focus"> <a class="zj-del-target" href="/article/9656" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/4.jpg" alt="" title=""></a> </div> <span id="br5n5555bvll" class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/9656';}else{window.open('/article/9656');}" style="cursor: pointer;">Ctrl+L選擇整行(按住-繼續選擇下行)Ctrl+KK從光標處刪除至行尾Ctrl+Shift+K刪除整行Ctrl+Shift+D復制光標所在整行，插入在該行之前Ctrl+J合并行(已選擇需要合并的多行時)Ctrl+KU改為大寫Ctrl+KL改為小寫Ctrl+D選詞(按住-繼續選擇下個相同的字符串)Ctrl+M光標移動至括號內開始或結束的位置Ctrl+Shift+M選擇括號內的內容(按住-繼續選擇父括號)Ctrl+/注釋整行(如已選擇內容，同“Ctrl+S</span> <p class="auth-span"> <span id="br5n5555bvll" class="muted"><i class="fa fa-user"></i><span id="br5n5555bvll" class="zj-icon-text">系統</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-clock-o"></i><span id="br5n5555bvll" class="zj-icon-text">2019-08-12 09:27:00</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-eye"></i><span id="br5n5555bvll" class="zj-icon-text">2050</span></span>  </p> </article><article class="excerpt"> <header> <a title="Python" class="label label-important zj-del-target" href="/category/44">Python<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/30447" title="python迭代器實例簡析" target="_blank" onclick="return recordId('',)">python迭代器實例簡析 </a> </h2> </header> <div id="br5n5555bvll" class="focus"> <a class="zj-del-target" href="/article/30447" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/7.jpg" alt="" title=""></a> </div> <span id="br5n5555bvll" class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/30447';}else{window.open('/article/30447');}" style="cursor: pointer;">本文實例講述了python迭代器的簡單用法，分享給大家供大家參考。具體分析如下：生成器表達式是用來生成函數調用時序列參數的一種迭代器寫法生成器對象可以遍歷或轉化為列表（或元組等數據結構），但不能切片(slicing)。當函數的唯一的實參是可迭代序列時，便可以去掉生成器表達式兩端>的圓括號，寫出更優雅的代碼：>>>>sum(iforiinxrange(10))45sum聲明：sum(iterable[,start])Sumsstartandtheitemso</span> <p class="auth-span"> <span id="br5n5555bvll" class="muted"><i class="fa fa-user"></i><span id="br5n5555bvll" class="zj-icon-text">系統</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-clock-o"></i><span id="br5n5555bvll" class="zj-icon-text">2019-09-27 17:56:32</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-eye"></i><span id="br5n5555bvll" class="zj-icon-text">2049</span></span>  </p> </article><article class="excerpt"> <header> <a title="Python" class="label label-important zj-del-target" href="/category/44">Python<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/30032" title="Python學習之asyncore模塊用法實例教程" target="_blank" onclick="return recordId('',)">Python學習之asyncore模塊用法實例教程 </a> </h2> </header> <div id="br5n5555bvll" class="focus"> <a class="zj-del-target" href="/article/30032" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/2.jpg" alt="" title=""></a> </div> <span id="br5n5555bvll" class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/30032';}else{window.open('/article/30032');}" style="cursor: pointer;">本文以實例分析了Python中asyncore模塊的原理及用法，分享給大家供大家參考。具體分析如下：asyncore庫是python的一個標準庫，它是一個異步socket的包裝。我們操作網絡的時候可以直接使用socket等底層的庫，但是asyncore使得我們可以更加方便的操作網絡，避免直接使用socket，select，poll等工具時需要面對的復雜。這個庫很簡單，包含了一個函數和一個類*loop()函數*dispatcher基類需要注意的是，loop函</span> <p class="auth-span"> <span id="br5n5555bvll" class="muted"><i class="fa fa-user"></i><span id="br5n5555bvll" class="zj-icon-text">系統</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-clock-o"></i><span id="br5n5555bvll" class="zj-icon-text">2019-09-27 17:55:57</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-eye"></i><span id="br5n5555bvll" class="zj-icon-text">2049</span></span>  </p> </article><article class="excerpt"> <header> <a title="Python" class="label label-important zj-del-target" href="/category/44">Python<i class="label-arrow"></i></a> <h2> <a class="zj-titles zj-del-target" href="/article/29998" title="用pickle存儲Python的原生對象方法" target="_blank" onclick="return recordId('',)">用pickle存儲Python的原生對象方法 </a> </h2> </header> <div id="br5n5555bvll" class="focus"> <a class="zj-del-target" href="/article/29998" target="_blank"><img style="width: 200px; height: 123px;" class="thumb" src="/Public/static/images/article/8.jpg" alt="" title=""></a> </div> <span id="br5n5555bvll" class="note" onclick="if (jq.browser.versions.mobile) {window.location.href='/article/29998';}else{window.open('/article/29998');}" style="cursor: pointer;">在Python中存儲數據到文件中時，簡單的做法是調用open函數執行文件寫入操作，但是這樣做的話，當我們要重新讀取文件內容時，就會出現類型不匹配的情況，因為讀取的都是字符串的形式，所以還需要進行類型轉換，這樣不簡潔?；蛘呤褂胑val函數把字符串轉換為對象，但是有時它過于強大，它會執行Python的任何表達式，甚至做出威脅系統正常工作的表達式，這樣做不安全。如果想存儲Python原生對象，但又無法信賴文件的數據來源，那么pickle模塊會是個理想的選擇。pi</span> <p class="auth-span"> <span id="br5n5555bvll" class="muted"><i class="fa fa-user"></i><span id="br5n5555bvll" class="zj-icon-text">系統</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-clock-o"></i><span id="br5n5555bvll" class="zj-icon-text">2019-09-27 17:55:55</span></span> <span id="br5n5555bvll" class="muted"><i class="fa fa-eye"></i><span id="br5n5555bvll" class="zj-icon-text">2049</span></span>  </p> </article><div id="br5n5555bvll" class="pagination" style="display:;"> <ul><li><a href="/search/p/1">首頁</a></li> <li id="br5n5555bvll" class="prev-page"><a href="/search/p/2450">上一頁</a></li> <li><a href="/search/p/2449">2449</a></li><li><a href="/search/p/2450">2450</a></li><li id="br5n5555bvll" 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