Recursive articles（遞歸篇）

Feibo sequence

            
              def fib(number):
    if number==0 or number == 1:
        return number

    else:
        return fib(number-1) + fib(number-2)

for i in range(8):
    print("fib(%2d) = %2d" % (i,fib(i)))
            
          

We can control the time of the function.

            
              def fib(number):
    if number==0 or number == 1:
        return number

    else:
        return fib(number-1) + fib(number-2)
while True:
    a = int(input("How many do you want?"
                  "\nThis integer must be > 0"
                  "Please enter your integer:"))
    if a < 0:
        print("The integer of you enter is wrong，please enter again！\n")
        continue
    for i in range(a+1):
        print("fib(%d) = %2d" % (i,fib(i)))
    print()
            
          

List's using methods.

            
              # creating an empty list
list = []

# add new value to the list
for number in range(1,11):
    list += [ number ]

print(list)
print()
# len(list) is the method to get the length of the list
print("There are",len(list),"elements in the list")
print()

# print the values in list
i = 0
for item in list:

    print("list[%d] is %d"%(i,item))
    i += 1
print()

# change the value in list
list[0] = 100
# if the index lower than 0
# it will Count from the right
# this is a logical error that is not serious
# better never use it!!!!!
list[-3] = 999
print(list)
            
          

Dictionary

            
              # creating empty dictionary
empty_dictionary={"name":"No"}

# creating another dictionary
grade={"name":"Sabo",
       "grade":"Good!",
       }

# output the grade
print("grade dictionary is")
print(grade)
print()

# add to our empty dictionary
print("before add grade")
print("empty_dictionary is ")
print(empty_dictionary)
print()

print("after add grade")
print("empty_dictionary is ")
empty_dictionary.update(grade)
print(empty_dictionary)
            
          

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