原創(chuàng)于2009年08月02日，2009年10月22日遷移至此。
Oracle 分析函數(shù)—— CUBE ， ROLLUP
CUBE
功能描述：
注意：
ROLLUP
功能描述：
注意：
如果是 ROLLUP(A, B, C) 的話， GROUP BY 順序
(A 、 B 、 C)
(A 、 B)
(A)
最后對(duì)全表進(jìn)行 GROUP BY 操作。
如果是 GROUP BY CUBE(A, B, C) ， GROUP BY 順序
(A 、 B 、 C)
(A 、 B)
(A 、 C)
(A) ，
(B 、 C)
(B)
(C) ，
最后對(duì)全表進(jìn)行 GROUP BY 操作。
CREATE TABLE studentscore
(
student_name varchar2(20),
subjects varchar2(20),
score number
)
INSERT INTO studentscore VALUES('WBQ','ENGLISH',90);
INSERT INTO studentscore VALUES('WBQ','MATHS',95);
INSERT INTO studentscore VALUES('WBQ','CHINESE',88);
INSERT INTO studentscore VALUES('CZH','ENGLISH',80);
INSERT INTO studentscore VALUES('CZH','MATHS',90);
INSERT INTO studentscore VALUES('CZH','HISTORY',92);
INSERT INTO studentscore VALUES('CB','POLITICS',70);
INSERT INTO studentscore VALUES('CB','HISTORY',75);
INSERT INTO studentscore VALUES('LDH','POLITICS',80);
INSERT INTO studentscore VALUES('LDH','CHINESE',90);
INSERT INTO studentscore VALUES('LDH','HISTORY',95);
SELECT
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects);
等同于以下標(biāo)準(zhǔn) SQL
SELECT NULL,subjects,SUM(score)
FROM studentscore
GROUP BY subjects
UNION
SELECT student_name,NULL,SUM(score)
FROM studentscore
GROUP BY student_name
UNION
SELECT NULL,NULL,SUM(score)
FROM studentscore
UNION
SELECT student_name,subjects,SUM(score)
FROM studentscore
GROUP BY student_name,subjects
SELECT
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects);
SELECT student_name,NULL,SUM(score)
FROM studentscore
GROUP BY student_name
UNION
SELECT NULL,NULL,SUM(score)
FROM studentscore
UNION
SELECT student_name,subjects,SUM(score)
FROM studentscore
GROUP BY student_name,subjects
SELECT
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1,2;
SELECT
grouping(student_name),
grouping(subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects)
ORDER BY 1,2;
SELECT
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1;
SELECT
grouping_id(student_name,subjects),
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY ROLLUP(student_name,subjects)
ORDER BY 1;
SELECT
grouping(student_name),
grouping(subjects),
CASE WHEN grouping(student_name)=0 AND grouping(subjects)=1 THEN ' 學(xué)生成績(jī)合計(jì) '
WHEN grouping(student_name)=1 AND grouping(subjects)=0 THEN ' 課目成績(jī)合計(jì) '
WHEN grouping(student_name)=1 AND grouping(subjects)=1 THEN ' 總 計(jì) '
ELSE ''
END SUMMARY,
student_name,
subjects,
sum(score)
FROM studentscore
GROUP BY CUBE(student_name,subjects)
ORDER BY 1,2;
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